kiwiguy said:
Assuming the adaptor is a passive device you could just wire it across the appropriate legs of the terminals. You could even make your own adapters knowing the right resistance.
REMINDER: This is all theory. I don't know what I'm taking about. Tony would know better.
Yes, you could run the parallel resistor between the communication pin and ground on the outside of the plug (no need to cut open).
Here's a simple formula that I stole off the internet to determine to total resistance measured in ohms from multiple resistors IN PARALLEL only:
RT = Resistance Total
1/R total = 1/R1 + 1/R2 + 1/R3, etc.
So,
R1 = 33k Ω
R2 = 36k Ω
1/RT = 1/33k + 1/36k
1/RT = 36k/1,188,000k + 33k/1,188,000k
1/RT = 69k/1,188,000k
1/RT = 0.00005808
RT = 17.2k Ω
The total resistance is 17.2k Ω
That should be about 32 amps.
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Tesla UMC Plugs Resistance
40 amps - 9.08k ohms
24 amps - 33.16k ohms
16 amps - 75k ohms
12 amps - 140k ohms